Carlo 
Hi,
Why do we specify in linker scripts the entry point using ENTRY(symbol)
when for example the ARM architecture always starts its reset code at
address 0x0000000?
I have a snippet of a linker script as following (taken from barebox
bootloader sources)
OUTPUT_FORMAT("elf32-littlearm", "elf32-littlearm", "elf32-littlearm")
OUTPUT_ARCH(arm)
ENTRY(exception_vectors)
SECTIONS
{
. = TEXT_BASE;
PRE_IMAGE
. = ALIGN(4);
.text :
{
_stext = .;
_text = .;
*(.text_entry*)
...
With the code for reset handler in .text_entry section:
void __naked __section(.text_entry) exception_vectors(void)
{
__asm__ __volatile__ (
"b reset\n" /* reset */
...
Now, since TEXT_BASE is different from 0x00000000, how can reset be at
location 0x00000000 where it is expected to be? (i.e. if TEXT_BASE is
0x80000000, then reset is at 0x80000000 according to the linker script
whereas the first instruction to be executed by the CPU should be
located at 0x00000000).
Is there memory aliasing in this case or the ENTRY is used for this
purpose?
Thank you,
--
Carlo