usb_5v pin

hi.
where must usb_5v be connected to?
in schematic there is no node connected to it.

where must usb_5v be connected to?
there is no node connected to it?

Pretty sure you will find it is connected to VDD5V.  But, you are right it
is not shown on the circuit.

Ohmmeter should soon tell you.

thanks for your answer.
But I checked this pin on micro 2440 Board,using Multi-metter(short circuit
Test), unfortunately it`s not connected to VDD5v.
bests.

an other thing that is,if you connect this pin internally to VDD5V,when you
plug computer usb cable in this port,you will make a short circuit between
VDD5V(evaluation board) and your PC 
thanks

Sorry, if based on my initial incorrect information you went ahead and
connected it up.

On the unmodified board if it is not connected to 5V then how does a USB
host device get it's 5V to operate.

I thought you were talking about the USB host connector.  Apparently, you
were referring to the USB slave connector.  If so, I didn't understand
correctly.

Any damage?

Regards,
Dave

Looking at the circuit I am still confused.

It appears to me now that they have swapped the labelling on these two
jacks.

Is that your understanding?

Ignore the 2nd sentence.

And the 3rd as I was referencing the schematic diagram :(

NO EVERY THING IS OK.
YES YOU ARE RIGHT.I`M SPEAKING ABOUT SLAVE USB.
WHERE IS USB_5V CONNECTED TO?
AND AN OTHER NEW QUESTION ,WHAT ABOUT NANDBOOT PIN?

THANKS AGAIN FOR YOU EXTRA ATTENTION

After "sleeping on" this issue, I want to provided a more careful
explanation.

Normally, for a USB powered device (the mini2440 being connected to the
computer in your case) the usb_5V WOULD be connected to VDD5V. However,
because the mii2440 with the touchscreen enabled draws more than 0.5A then
maybe FriendlyArm decided to leave this dis-connected and expect you to
power the mini2440 from an external supply.  See
http://en.wikipedia.org/wiki/USB especially here:
To quote -
A unit load is defined as 100 mA in USB 2.0, and was raised to 150 mA in
USB 3.0. A maximum of 5 unit loads (500 mA) can be drawn from a port in USB
2.0, which was raised to 6 (900 mA) in USB 3.0.

The usb_5V should be a line coming from the computer that would be used for
supplying usb devices.

In your case, connecting the usb_5V to Vdd5V AND I assume plugging in the
plug pack would result in the two nominal 5Volt supplies equalising to a
common voltage and one of them supplying more current than the other due to
their different designs. No problem here.

If from the beginning you were powering the mini2440 from the plug pack AND
plugging the mini2440 into the computer USB port then you should have had a
correctly powered system. I can't comment regarding it being a  properly
operating setup, there could be other issues.

Looking at the labelling on the schematic and page 10 of the
mini2440_manual.pdf that only label that is consistent is the port they
have identified as the USB host.  The other connector is labelled <USB
device> on the schematic and <USB slave> in the manual. Under the both
connectors is another label which suggests they are both USB port A type. 
I suggest that the terms need to be clarified!

I apologise for not getting back to your first reply in a timely manner.

Dave